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Singular measure

In mathematics, two positive measures and defined on a measurable space are called singular if there exist two disjoint measurable sets whose union is such that is zero on all measurable subsets of while is zero on all measurable subsets of This is denoted by

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In mathematics, two positive (or signed or complex) measures μ {\displaystyle \mu } and ν {\displaystyle \nu } defined on a measurable space ( Ω , Σ ) {\displaystyle (\Omega ,\Sigma )} are called singular if there exist two disjoint measurable sets A , B Σ {\displaystyle A,B\in \Sigma } whose union is Ω {\displaystyle \Omega } such that μ {\displaystyle \mu } is zero on all measurable subsets of B {\displaystyle B} while ν {\displaystyle \nu } is zero on all measurable subsets of A . {\displaystyle A.} This is denoted by μ ν . {\displaystyle \mu \perp \nu .}

A refined form of Lebesgue's decomposition theorem decomposes a singular measure into a singular continuous measure and a discrete measure.

Examples on Rn

As a particular case, a measure defined on the Euclidean space R n {\displaystyle \mathbb {R} ^{n}} is called singular, if it is singular with respect to the Lebesgue measure on this space. For example, the Dirac delta function is a singular measure.

Example. A discrete measure.

The Heaviside step function on the real line, H ( x )   = d e f { 0 , x < 0 ; 1 , x 0 ; {\displaystyle H(x)\ {\stackrel {\mathrm {def} }{=}}{\begin{cases}0,&x<0;\\1,&x\geq 0;\end{cases}}} has the Dirac delta distribution δ 0 {\displaystyle \delta _{0}} as its distributional derivative. This is a measure on the real line, a "point mass" at 0. {\displaystyle 0.} However, the Dirac measure δ 0 {\displaystyle \delta _{0}} is not absolutely continuous with respect to Lebesgue measure λ , {\displaystyle \lambda ,} nor is λ {\displaystyle \lambda } absolutely continuous with respect to δ 0 : {\displaystyle \delta _{0}:} λ ( { 0 } ) = 0 {\displaystyle \lambda (\{0\})=0} but δ 0 ( { 0 } ) = 1 ; {\displaystyle \delta _{0}(\{0\})=1;} if U {\displaystyle U} is any non-empty open set not containing 0, then λ ( U ) > 0 {\displaystyle \lambda (U)>0} but δ 0 ( U ) = 0. {\displaystyle \delta _{0}(U)=0.}

Example. A singular continuous measure.

The Cantor distribution has a cumulative distribution function that is continuous but not absolutely continuous, and indeed its absolutely continuous part is zero: it is singular continuous.

Example. A singular continuous measure on R 2 . {\displaystyle \mathbb {R} ^{2}.}

The upper and lower Fréchet–Hoeffding bounds are singular distributions in two dimensions.

See also

See also

References

References

  • Eric W Weisstein, CRC Concise Encyclopedia of Mathematics, CRC Press, 2002. ISBN 1-58488-347-2.
  • J Taylor, An Introduction to Measure and Probability, Springer, 1996. ISBN 0-387-94830-9.

This article incorporates material from singular measure on PlanetMath, which is licensed under the Creative Commons Attribution/Share-Alike License.